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05holtel
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Homework Statement
Consider the electric field created by a very long charged line of negative linear charge density -2.50 nC/m.
A small positive point charge of 8 mC moves from a distance of 9 cm to a distance of 17 cm.
How much work is done by the electric field?
Hint: The electric field for a long charged line is:
The Equation is E line = 1/(4piE0)(2lamda/r)
Express the result in the unit mJ and to three significant figures.
Homework Equations
The Equation is E line = 1/(4piE0)(2lamda/r)
The Attempt at a Solution
Is this hint equation provided equivalent to Gauss' Law: (2*pi*R*L*E = L*q/eo)
where eo is the coulomb's law constant "epsilon-zero" = 8.89^10^-12 N*m^2/C^2
and q is the charge per unit length
Therefore,
E(R) = q/(2 pi eo R)
Multiply that by Q = 8 mC and integrate with dR from R = 0.09 to 0.17 m
Also I am confused how to integrate this