1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

H= (NI)/ (2(Pi)r)

  1. Nov 14, 2008 #1
    1. The problem statement, all variables and given/known data
    [​IMG]


    2. Relevant equations

    H= (NI)/ (2(Pi)r)
    V=IR

    3. The attempt at a solution

    a)

    total resitance = 100ohms?
    from this would the current be 0.12A

    over 1ohm resistor: 0.12V

    not sure if this is correct even. Any help would be much appreciated.
     
  2. jcsd
  3. Nov 15, 2008 #2

    Defennder

    User Avatar
    Homework Helper

    Re: conductance

    I think you misread 'H' here. H in the question doesn't refer to the magnetic field strength and the formula you provided here refers to the H-field in a torus.

    Also in your answer you disregarded the inductor. Bear in mind that once you open the circuit, you can't treat the inductor as a short-circuited wire. What you should do is to write out the KVL loop equation, bearing in mind the potential drop across the inductor is L(di/dt), where i is the time-varying current through the inductor. Then you'll get a differential equation which you then have to solve for the current. Plugging in a initial value will help you find the unknown constant of integration.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: H= (NI)/ (2(Pi)r)
  1. The program R (Replies: 2)

  2. T to pi conversion (Replies: 16)

Loading...