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H= (NI)/ (2(Pi)r)

  1. Nov 14, 2008 #1
    1. The problem statement, all variables and given/known data
    123986[/ATTACH]"] physics.jpg

    2. Relevant equations

    H= (NI)/ (2(Pi)r)

    3. The attempt at a solution


    total resitance = 100ohms?
    from this would the current be 0.12A

    over 1ohm resistor: 0.12V

    not sure if this is correct even. Any help would be much appreciated.

    Attached Files:

  2. jcsd
  3. Nov 15, 2008 #2


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    Homework Helper

    Re: conductance

    I think you misread 'H' here. H in the question doesn't refer to the magnetic field strength and the formula you provided here refers to the H-field in a torus.

    Also in your answer you disregarded the inductor. Bear in mind that once you open the circuit, you can't treat the inductor as a short-circuited wire. What you should do is to write out the KVL loop equation, bearing in mind the potential drop across the inductor is L(di/dt), where i is the time-varying current through the inductor. Then you'll get a differential equation which you then have to solve for the current. Plugging in a initial value will help you find the unknown constant of integration.
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