1. Oct 27, 2005 #1

   Struggling

   

   hi can anyone explain to me how to get the H value for runge kutta second method? ive searched everywhere online but i just dont understand it.
   
   if found h = tn - to/n??
   
   i know what value of "to" is but no clue what values to put in for n and tn?
   
   thanks

    

   Struggling, Oct 27, 2005
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3. Oct 27, 2005 #2

   Integral

   

   Staff Emeritus

   Science Advisor

   Gold Member

   If I am interpreting what you are saying correctly, h is your time step, the errors of a 2nd order RK method are on the order of h⁵. It looks to me like your t₀ is the starting time, therefore t_n is the time end point, n is the number of time steps you are taking so your h is the time interval divided by the number of time steps.
   
   for example let:
   t₀=0
   t_n=100
   n=1000
   
   [tex] h = \frac {t_n - t_0} n = \frac {100 - 0} {1000} = .1 [/tex]

    

   Last edited: Oct 27, 2005

   Integral, Oct 27, 2005

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