1. The problem statement, all variables and given/known data pH fluctuations need to be determined at a maximum dosage of 50mg/L of 93% sulphuric acid . 2. Relevant equations If the start pH of the water sample is 8, how much will pH be lowered by adding of 50mg/L of 93% sulphuric acid, and what is the correlation between the different mass/volumes added and pH fluctuations. 3. The attempt at a solution First, I have tried to find out what would be the pH of 50mg/l of 93% H2SO4 and from given data i have calculated molarity: Concentration * Density or Specific Quantity / Molar Mass = Molarity (0.930) *(0.05g/L):( 98.079 g/mol)=0.0004741 H2SO4 --> 2 H+ + SO4-2 H2SO4 is a strong acid so concentration of [H+]=Molarity pH=-log[H+]=-log(2x0.0004741)= 3.0231 However, this is where the calculation stops, since i don't know how to calculate the final pH I am even wondering was this right way to start the calculation.. Please help... Thank you!