Hadron Cross Section Calculation

  • Thread starter benjammin
  • Start date
  • #1
6
0
Hi all,

I'm trying to understand the solution to a problem from a textbook. We're asked to find the proportionality constant for $$\frac{d\sigma_{\rm elastic}}{dq^2}\propto e^{bt},$$ where q is the momentum transfer in a scattering process, defined in elastic scattering as $$q=2p\sin(\theta/2).$$ So the solution says to make the following argument: $$\frac{d\sigma_{\rm elastic}}{dq^2}=\frac{d\sigma_{\rm elastic}}{d\Omega}\frac{d\Omega}{dq^2}=\lambda/2\frac{d\sigma_{\rm elastic}}{d\Omega}.$$ Which seems to imply that $$\frac{d\Omega}{dq^2}=\lambda/2.$$ I just don't understand that step. Does anyone have any ideas?

Thanks!
 

Answers and Replies

Related Threads on Hadron Cross Section Calculation

  • Last Post
Replies
5
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
0
Views
785
Replies
1
Views
2K
Replies
2
Views
2K
  • Last Post
Replies
0
Views
2K
Replies
2
Views
2K
  • Last Post
Replies
2
Views
6K
  • Last Post
Replies
7
Views
2K
  • Last Post
Replies
2
Views
4K
Top