(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The half-life of iodine-131, an isotope used in the treatment of thyroid disorders, is 8.04 d.

(a) If a sample of iodine-131 contains 8.5 1016 nuclei, what is the activity of the sample? Express your answer in curies.

(b) If the half-life of iodine-131 were only one-fourth of its actual value, would the activity of this sample be increased or decreased? Explain.

(c) Calculate the factor by which the activity of this sample would change under the assumptions stated in part (b).

2. Relevant equations

R = l deltaN/deltat l = lambdaN

1 Ci = 3.7 x 10^10 decays/s

3. The attempt at a solution

For part (a)

8.04 d x 24hr/1d x 60min/1hr x 60s/1min = 694,656 s

R = l deltaN/deltat l = lambdaN = (8.5 x 10^16 nuclei)/(694,656 s) = 1.2236 x 10^11

1.2236 x 10^11 x 1s/3.6 x to^10 decays = 3.307 x 10^-22 Ci

Can you please check if I did this correctly?

For Part (b), if the half-life of iodine-131 were only one-fourth of its actual value, the activity of this sample would be increased because there is an inverse relationship between the two.

I do not know how to approach part (c), so I would like to request help for that section. Thanks.

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# Half-life problem

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