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Half-reactions and EMF

  • #1

Homework Statement


Based only on the half-reactions in the table, which of the following is the strongest oxidizing agent?
(See attachment)

Homework Equations




The Attempt at a Solution


I noticed in this table that not all elements are in the reduction form. I flipped them around and changed the sign, however, the correct answer states that Cd2+ is the correct answer. Shouldn't it be F-? Thanks in advance.
 

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Answers and Replies

  • #3
... an oxidizing agent?
Ok, I typed that wrong. According to the chart, we know that the the half reaction: 2F-→F2 + 2e- has potential of -2.87 V. But this is being oxidized. Don't we have to flip it and change it to the reduction half reaction to compare it to the rest of the agents listed?
 
  • #4
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No. F/F2 is an oxidizing agent; F- is a reducing agent.
 
  • #5
Right, so wouldn't so wouldn't 2F-→F2+ 2e- be the strongest oxidizing agent and not Cd2++2e-→Cd? I think the book is wrong in this one.
 
  • #6
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NO. The half reactions are written with both species; you are not being asked to pick a half reaction, just a single species.
 

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