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Half-reactions and EMF

  1. Feb 19, 2016 #1
    1. The problem statement, all variables and given/known data
    Based only on the half-reactions in the table, which of the following is the strongest oxidizing agent?
    (See attachment)

    2. Relevant equations


    3. The attempt at a solution
    I noticed in this table that not all elements are in the reduction form. I flipped them around and changed the sign, however, the correct answer states that Cd2+ is the correct answer. Shouldn't it be F-? Thanks in advance.
     

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  2. jcsd
  3. Feb 19, 2016 #2

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    ... an oxidizing agent?
     
  4. Feb 19, 2016 #3
    Ok, I typed that wrong. According to the chart, we know that the the half reaction: 2F-→F2 + 2e- has potential of -2.87 V. But this is being oxidized. Don't we have to flip it and change it to the reduction half reaction to compare it to the rest of the agents listed?
     
  5. Feb 19, 2016 #4

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    No. F/F2 is an oxidizing agent; F- is a reducing agent.
     
  6. Feb 19, 2016 #5
    Right, so wouldn't so wouldn't 2F-→F2+ 2e- be the strongest oxidizing agent and not Cd2++2e-→Cd? I think the book is wrong in this one.
     
  7. Feb 19, 2016 #6

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    NO. The half reactions are written with both species; you are not being asked to pick a half reaction, just a single species.
     
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