- #1
foxandthehen
- 13
- 0
1.
Determine the half value thickness, X(1/2) for lead where;
I = 0.4 MeV
u = 1.59cm^-1
2.
using;
I = Io e^-ux3.
ln(I/Io) = ln(e) -ux
ln(2) / -1.59x10^-2 = X(1/2)
=> X(1/2) = -1.7523m
Is that right?
Determine the half value thickness, X(1/2) for lead where;
I = 0.4 MeV
u = 1.59cm^-1
2.
using;
I = Io e^-ux3.
ln(I/Io) = ln(e) -ux
ln(2) / -1.59x10^-2 = X(1/2)
=> X(1/2) = -1.7523m
Is that right?