- #1

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## Homework Statement

## Homework Equations

## The Attempt at a Solution

$$Δ{ V }_{ H }=\frac { IB }{ nqt } \\ 9.6*{ 10 }^{ -6 }=\frac { 50*1.3 }{ n*e*3.3*{ 10 }^{ -4 } } \\ n=1.28*{ 10 }^{ 29 }\quad electrons/{ m }^{ 3 }$$

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- Thread starter Turion
- Start date

- #1

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$$Δ{ V }_{ H }=\frac { IB }{ nqt } \\ 9.6*{ 10 }^{ -6 }=\frac { 50*1.3 }{ n*e*3.3*{ 10 }^{ -4 } } \\ n=1.28*{ 10 }^{ 29 }\quad electrons/{ m }^{ 3 }$$

- #2

mfb

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You can use WolframAlpha to check calculations like that.

- #3

- 143

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You can use WolframAlpha to check calculations like that.

I thought the method was wrong because it gives us d=1mm but we don't use it in our calculations.

- #4

mfb

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I'm not sure where the Hall voltage is measured, either 0.330mm or 1mm is not necessary.

- #5

gneill

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