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Hall-petch equation

  1. Sep 3, 2011 #1
    1. The problem statement, all variables and given/known data
    I've attached the question.


    2. Relevant equations
    σy = σo + k(d^-(1/2))


    3. The attempt at a solution

    450 x 10^6 =σo + k / sqrt(17 x 10^-6)-------------1
    565 x 10^6 =σo + k / sqrt (0.8 x 10^-6)------------2

    σo = 4.18142 x 10^8 Pa and k = 131354

    is that right for the first part???

    the second part: σy =4.18142 x 10^8 + 131354 / sqrt(0.2 x 10^-6)

    σy = 7.11858 x 10^-6 Pa

    is that correct???
     

    Attached Files:

  2. jcsd
  3. Sep 3, 2011 #2
    I got the same numbers for the first part and for the second part I think you are off by a factor of one hundred?
     
  4. Sep 3, 2011 #3

    lewando

    User Avatar
    Gold Member

    I think the strength of titanium is on the order of MPa, not μPa.
     
  5. Sep 3, 2011 #4
    Did not notice the minus sign, the second answer I got was about σy = 7.1 x 10^8 Pa
     
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