- #1

Felipe Lincoln

Gold Member

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- 11

## Homework Statement

I have initially a capacitor with capacitance ##C_1## with charge ##Q_1>0## and energy ##U_1>0##. I put another capacitor ##C_2## with no charge ##C_2=0## in parallel with the first. We assume this is an ideal circuit. The charge will distribute to both capacitors and the total charge will be equal the initial ##\sum Q=Q_1##.

**a)**Why does the total energy at the final instant is less than the initial?

**b)**does it have some relation with the potential energy associated with the charge position?

**c)**If I remove these capacitor from the circuit and associate each of them separately with another capacitors ##C_3## and ##C_4## in parallel, and keep doing this forever, will I reach energy close to zero with the same initial charge ##C_1## ?

## Homework Equations

Capacitor's charge: $$Q=CV$$

Capacitor's energy: $$\dfrac{1}{2}CV^2$$

## The Attempt at a Solution

We always hear that the energy is taken away by the heating and electromagnetic radiation, I'm not satisfied with that once we did all the math considering them to be ideal.