The handle of a hammer is pushed with a force F = 103 N, at an angle θ = 12°, to pull out the nail at B. What is the moment of this force about point A, if L1 = 0.054 m and L2 = 0.32 m? My attempt So what I've been doing is finding the Force that is perpendicular to the two lengths, 0.054m and 0.32m. The force perpendicular to 0.054m is Fsinθ = 21.41 N The force perpendicular to 0.32m is Fcosθ = 100.75 N Now I've been using the formula Momenttotal = Moment 1 + Moment 2 M1 = (21.41N)*(0.054m) coming out of the page = 1.156 J M2 = (100.75N)*(0.32) going into the page = 32.24 J Then I've been going 32.24 - 1.156 = 31.084 J (going into the page). This answer hasn't been working for me. Any ideas? I know for certain that the moment is indeed pointing into the page, in the negative k-hat direction in this case.