An athlete starts to swing a hammer in a 2m radius circle which is tilted up on one side. Each complete 360 degree swing takes 0.71s. The angle of the plane of the circle to the horizontal is 45 degrees. The hammer is released at a height of 1.5m from the ground, at an angle of 45 degrees to the horizontal, while travelling at 18m/s. How far away does it land, assuming g=10ms-2 I started by coming up with parametric equations, which give the vertical (y) and horizontal (x) displacement as a function of time (t). [tex] x=18t sin(45)[/tex] [tex]y=18t cos(45) - 5t^2 [/tex] Since it was released from a heigh of 1.5m off the ground, the ground corrosponds to a displacement of -1.5m. So i set y=-1.5 and solved for t, giving t=2.658s. Then using this value in my 'x' equation, i get a horizontal displacement of 33.8m. Now, i checked the answer, and apparently it is 32.8m. Have i done something wrong, or is the 2 in the answer a typo?