An athlete jumps vertically. treat athlete as particle and Ymax is the maximum height above the floor the athlete achieves. To explain why he seems to hang in the air, calculate the ratio of the time he is above ymax/2 to the time it takes him to go from the floor to that height. we get 2 equations, Vymax/2 = V0Y-gt_1 Vymax = Vymax/2 - gt_2 after isolating t we get: 2t_2 / t_1 = 2 Vymax/2 / V0y-Vymax/2 V0Y - Vymax/2 < Vymax/2 <<<< how do you go about explaining this in common language?? the time it takes for person to reach ymax/2 from Yground is les thatn time it takes the person to reach Ymax from Ymax/2, so Vavg from Yground to Ymax/2 is greater thatn Ymax/2 to Ymax.