Solving Force on a Hanging Sign

In summary, the conversation was about a businessman hanging a sign outside his store and determining the tension in the wire holding the sign. The sign has a mass of 50 kg and is rigidly attached to the wall at the lower left corner. The options for the tension in the wire ranged from 87 N to 490 N, with the correct answer being 173 N. However, the question is flawed as the answer is only obtained if the sign can pivot freely about the bottom left corner, rather than being rigidly attached.
  • #1
fball558
147
0
hanging sign forces??

Homework Statement



PIC IS ATTACHED

A businessman is hanging a sign outside his store in the
fashion shown in the figure below. The sign has a mass of
50 kg. For a sign of this mass, what is the tension in the
wire? The sign is rigidly attached to the wall at the lower
left corner.

A. 346 N
B. 260 N
C. 490 N
D. 87 N
E. 173 N



The Attempt at a Solution



i am stuck. only thing i though of was find mg then find the sin of the angle
so i did mg sin (45)
490 sin (45) got 370.
which is not even close to letter E (which is the right answer)
 

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  • #2


If it's rigidly attached as it says in the question - then the tension in the wire is zero.
ie the sign would stay there without the wire

Normally in these question you assume the weight acts at the centre of the sign and take moments about the point that it joins the wall (assumed to pivot) to find the upward force at the outside end
 
  • #3


The question is flawed.
Answer E is obtained if you assume the sign
can pivot freely about the bottom left corner.of the sign.
(hardly "attached rigidly"!)

Remembor the pivot can exert a force on the sign, but no torque.

David
 
  • #4


davieddy said:
The question is flawed.
Answer E is obtained if you assume the sign
can pivot freely about the bottom left corner.of the sign.
(hardly "attached rigidly"!)

Remembor the pivot can exert a force on the sign, but no torque.

David


so if we assume the sign can pivot, how would you go about getting answer E??
 
  • #5


Take moments about the pivot
 

1. How do I calculate the force on a hanging sign?

To calculate the force on a hanging sign, you will need to know the weight of the sign and the angle at which it is hanging. Then, you can use the formula F = mg sinθ, where F is the force, m is the mass of the sign, g is the acceleration due to gravity, and θ is the angle of the sign.

2. What is the importance of solving for force on a hanging sign?

Solving for force on a hanging sign is important because it allows you to determine the amount of weight or force that is being exerted on the support structure. This information is crucial for ensuring the sign is properly installed and will not cause any safety hazards.

3. Can I use the same formula to calculate the force on any hanging object?

Yes, you can use the same formula to calculate the force on any hanging object as long as you know the weight and angle at which it is hanging. This formula is a basic principle of physics known as the law of gravitation.

4. How does the angle of the hanging sign affect the force?

The angle of the hanging sign directly affects the force on the sign. As the angle increases, the force also increases. This is because the component of the weight acting perpendicular to the support structure also increases.

5. What other factors should be considered when solving for force on a hanging sign?

Other factors that should be considered when solving for force on a hanging sign include the material and strength of the support structure, wind or other external forces that may act on the sign, and any additional weight or objects that may be attached to the sign.

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