Hanging Sign Problem and Pulley Problem

• Glenn K
In summary, the tension in cable1 in the Y direction + T in cable2 in the Y direction = -98.1 Newtons. The tension in cable1 in the X direction + T in cable2 in the X direction = 0 Newtons.
Glenn K
Okay, we've been studying this for a while but I still always seem to forget how to do these and they aren't anywhere in my Physics book.

Problem 1: Sign hanging at rest from two cables. One is angled at zero degrees while the other is at 135 degrees. The sign is 10kg. Find the tension of both cables.

Problem 2: Sign hanging at rest from two cables. One is angled at 170 degrees while the other is at 35 degrees. The sign is 500kg. Find the tension of both cables.

Problem 3: There's a frictionless pulley with two weights on either end of a string. One weight is 20kg while the other is 35kg. Find the acceleration of the 20kg mass and the tension of the cable.

For the first two I know you have to like do T1x + T2y = T1 and T2x + T1y + F = T2 or something, but I can't remember the right formula for it. For the second one I don't know how to do it at all.

Also, if anyone has any links on how to sum up masses that would be greatly appreciated.

I will do number 1 as an example:

(we assume the sign is hanging at rest supported by the cables)
cable1 is at 0 degree,
cable2 is at 135 degrees above the horizontal.

mass of sign = 10 kg, Force of weight = 10*9.81 = 98.1 Newtons

so both of those cables must be supporting a combined 98.1 Newtons of wieght.
Tension in Cable1 in the Y direction + T in cable2 in the Y direction = -98.1 N
Tension in Cable1 in the X direction + T in cable2 in the X direction = 0 N

cable1 holds no weight in the Y direction, all of it is held by cable2 since it is the only cable with an upward component to its angle.
F*sin(135) = 98.1, F = 138.7 N at an angle of 135 degrees,
no being at 135 degrees, some of that force is in the X direction, that is where cable1 comes into play, its tention must cancel out cable2's X direction tention,
Fx of cable2 = 138.7*cos(135) = -98.1 N, therefore cable1 must be supplying 98.1 N in the positive direction to cancel out the -98.1 N.

UNderstand, you need to break down the cables so that first, they (together) will hold up the sign, and then so that the sign doesn't move either direction because of some imbalanced X direction force.

Okay, I worked that out on paper and got it, but I'm having one heck of a time trying to figure out the second hanging sign problem. Do I need to find the two equations and substitute one in for the other? For the second one right now I have:

T2= -T1cos170/cos35 and T1=4900-T2sin35

Do I need to substitute one equation in the other to find the two tensions, or did I just do that totally wrong?

1. What is the Hanging Sign Problem?

The Hanging Sign Problem is a physics problem that involves calculating the tension and force on a sign that is hanging from two ropes attached to a wall. It is a common example used to demonstrate the principles of equilibrium and forces acting on an object.

2. How is the Hanging Sign Problem solved?

The Hanging Sign Problem can be solved using the principles of static equilibrium, which states that the sum of all forces acting on an object at rest must be equal to zero. By setting up equations for the forces acting on the sign and solving for the unknown variables, the tension and force on the sign can be determined.

3. What is the Pulley Problem?

The Pulley Problem is a physics problem that involves calculating the tension and force on a rope that is wrapped around a pulley and attached to a mass. It is a common example used to demonstrate the principles of mechanical advantage and the role of pulleys in lifting objects.

4. How is the Pulley Problem solved?

The Pulley Problem can be solved by considering the principles of mechanical advantage and the concept of work. By setting up equations for the forces acting on the pulley system and using the equation W=Fd to calculate the work done on the system, the tension and force on the rope can be determined.

5. What are some real-life applications of the Hanging Sign and Pulley Problems?

The principles demonstrated in the Hanging Sign and Pulley Problems have real-life applications in engineering, construction, and mechanics. For example, engineers use these principles to design structures and machines that can support heavy loads. The principles are also used in everyday objects such as elevators and cranes.

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