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Hanging sign problem

  1. Nov 22, 2004 #1
    A shop sign weighing 206 N is supported by a uniform 132 N beam of length L = 1.89 m as shown in figure below.

    The guy wire is connected D = 1.19 m from the backboard. Find the tension in the guy wire. Assume theta = 43.0 o
    Find the horizontal force exerted by the hinge on the beam.
    Find the vertical force exerted by the hinge on the beam. Use "up" as the positive direction.

    I get T = -mg * 1/2L + T*L*sin(43) = T = mg/2sin(40)

    Fx = Hx -T cos(43) = 0
    Hx = T cos(43)
    Fy = Hy -mg + Tsin(43) = 0
    Hy = mg - Tsin(43)

    But these are incorrect. Where did I go wrong?
     

    Attached Files:

  2. jcsd
  3. Nov 22, 2004 #2

    arildno

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    "I get T = -mg * 1/2L + T*L*sin(43) = T = mg/2sin(40)"

    This is complete nonsense!

    You have 3 forces creating torques about the hinge. Which, and where do they act?
     
  4. Nov 22, 2004 #3
    That wasn't suppose to be torque but rather tension.
     
  5. Nov 22, 2004 #4

    arildno

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    It's still nonsense, since your units don't match (T and TL have not the same units)
     
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