Hi, Ok I'm havin troubles trying to solve this calculus problem. -Rolling a Ball Bearing- A ball bearing is placed on an incline plane and begins to roll. The angle of elevation of the plane is θ. The distance (in meters) the ball bearing rolls in t seconds is s(t) = 4.9(sin θ)t^2 a. Determine the speed of the ball bearing. b. What value of θ will produce the maximum speed at a particular time. Ok so here is how I "tackled" the problem. ok part a, asks for speed so I take the derivative of the function to get velocity. v(t) = (0)(sin θ)(t^2) + (4.9)(cos θ)(t^2) + (4.9)(sin θ)(2t) v(t) = 4.9(t^2)(cos θ) + (9.8t)(sin θ) ok now from here I'm not sure if my next steps are right... Ok since they asked for the speed, i'm assuming they want an actual value....versus what I have thus far.... ok now setting what I have for v(t) to zero, I solve for t, thus I get: t = -2tan θ Now I take that value and put it back in to my original equation. Now I have s(t) = 4.9(sin θ)(-2tan θ)^2 Now I solve for θ, by setting s(t) equal to zero. but I end up with this.... 4 = (cos θ)^2, and I don't think this is the right answer... So any help on this would be nice, Thanks.