I am having trouble with the final part of this question - part f; I can do all the previous parts. I have attached the questions and markscheme, and so woulkd appreciate it if someone could just explain part (f) to me! Thanks alot.
If (f) is the part you are having trouble with, then presumably you have already proved that [itex]2x_n^2- (2n-1)x- (n+1)= 0[/itex] (part (e)). Now you want to find the smallest n such that [itex]x_n< n+ 0.05[/itex]. You could, for example, solve that using the quadrative formula and compare the solutions to n+ 0.05. Have you calculated some values of [itex]x_n[/itex]? What are [itex]x_0[/itex] [itex]x_1[/itex], etc.?
Thanks for the help. Im still confused as to how the markscheme answers have come about which I attached above. Thanks