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Homework Help: Hard Integral

  1. Mar 15, 2009 #1
    Nevermind, I seem to have figured it out

    1. The problem statement, all variables and given/known data
    show that:
    [tex]\int \frac{dN}{N} = \int_{0}^{\theta_max} \frac{dcos \theta}{2} \frac{1 + \frac{v^2}{v_0^2} cos(2 \theta ) }{ \sqrt{ 1 - \frac{v^2 sin^2 \theta}{v_0^2} } } [/tex]

    2. Relevant equations

    3. The attempt at a solution
    I'm having a lot of difficulty doing this...
    Note that [tex]sin(\theta_{max} ) = \frac{v_0}{v}[/tex]
    so after a bunch of algebra I get:

    [tex]\int \frac{dN}{N} = cot(\theta_{max} ) \int_{0}^{\theta_{max} } \frac{2y^2 - 1}{\sqrt{y^2 - 1} }[/tex]
    I am fairly confident that is correct because I keep on getting it.
    Unfortunately, I can't seem to integrate this at all.
    Last edited: Mar 15, 2009
  2. jcsd
  3. Mar 15, 2009 #2
    \int \frac{dN}{N} = cot(\theta_{max} ) \int_{0}^{\theta_{max} } \frac{2y^2 - 1}{\sqrt{y^2 - 1} }

    If you are finding it hard to integrate the right side, try u = sqrt(y^2-1) .. fairly simple to integrate
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