Nevermind, I seem to have figured it out

show that:

[tex]\int \frac{dN}{N} = \int_{0}^{\theta_max} \frac{dcos \theta}{2} \frac{1 + \frac{v^2}{v_0^2} cos(2 \theta ) }{ \sqrt{ 1 - \frac{v^2 sin^2 \theta}{v_0^2} } } [/tex]

I'm having a lot of difficulty doing this...

Note that [tex]sin(\theta_{max} ) = \frac{v_0}{v}[/tex]

so after a bunch of algebra I get:

[tex]\int \frac{dN}{N} = cot(\theta_{max} ) \int_{0}^{\theta_{max} } \frac{2y^2 - 1}{\sqrt{y^2 - 1} }[/tex]

I am fairly confident that is correct because I keep on getting it.

Unfortunately, I can't seem to integrate this at all.

**1. The problem statement, all variables and given/known data**show that:

[tex]\int \frac{dN}{N} = \int_{0}^{\theta_max} \frac{dcos \theta}{2} \frac{1 + \frac{v^2}{v_0^2} cos(2 \theta ) }{ \sqrt{ 1 - \frac{v^2 sin^2 \theta}{v_0^2} } } [/tex]

**2. Relevant equations****3. The attempt at a solution**I'm having a lot of difficulty doing this...

Note that [tex]sin(\theta_{max} ) = \frac{v_0}{v}[/tex]

so after a bunch of algebra I get:

[tex]\int \frac{dN}{N} = cot(\theta_{max} ) \int_{0}^{\theta_{max} } \frac{2y^2 - 1}{\sqrt{y^2 - 1} }[/tex]

I am fairly confident that is correct because I keep on getting it.

Unfortunately, I can't seem to integrate this at all.

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