1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Hard Integral

  1. Mar 15, 2009 #1
    Nevermind, I seem to have figured it out



    1. The problem statement, all variables and given/known data
    show that:
    [tex]\int \frac{dN}{N} = \int_{0}^{\theta_max} \frac{dcos \theta}{2} \frac{1 + \frac{v^2}{v_0^2} cos(2 \theta ) }{ \sqrt{ 1 - \frac{v^2 sin^2 \theta}{v_0^2} } } [/tex]


    2. Relevant equations



    3. The attempt at a solution
    I'm having a lot of difficulty doing this...
    Note that [tex]sin(\theta_{max} ) = \frac{v_0}{v}[/tex]
    so after a bunch of algebra I get:

    [tex]\int \frac{dN}{N} = cot(\theta_{max} ) \int_{0}^{\theta_{max} } \frac{2y^2 - 1}{\sqrt{y^2 - 1} }[/tex]
    I am fairly confident that is correct because I keep on getting it.
    Unfortunately, I can't seem to integrate this at all.
     
    Last edited: Mar 15, 2009
  2. jcsd
  3. Mar 15, 2009 #2
    [tex]
    \int \frac{dN}{N} = cot(\theta_{max} ) \int_{0}^{\theta_{max} } \frac{2y^2 - 1}{\sqrt{y^2 - 1} }
    [/tex]

    If you are finding it hard to integrate the right side, try u = sqrt(y^2-1) .. fairly simple to integrate
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Hard Integral
  1. Hard integral (Replies: 6)

  2. Hard Integral (Replies: 5)

  3. Hard integrals (Replies: 25)

  4. Hard integral (Replies: 5)

  5. Hard Integral (Replies: 8)

Loading...