Hard Integral

  • Thread starter roeb
  • Start date
  • #1
107
1
Nevermind, I seem to have figured it out



Homework Statement


show that:
[tex]\int \frac{dN}{N} = \int_{0}^{\theta_max} \frac{dcos \theta}{2} \frac{1 + \frac{v^2}{v_0^2} cos(2 \theta ) }{ \sqrt{ 1 - \frac{v^2 sin^2 \theta}{v_0^2} } } [/tex]


Homework Equations





The Attempt at a Solution


I'm having a lot of difficulty doing this...
Note that [tex]sin(\theta_{max} ) = \frac{v_0}{v}[/tex]
so after a bunch of algebra I get:

[tex]\int \frac{dN}{N} = cot(\theta_{max} ) \int_{0}^{\theta_{max} } \frac{2y^2 - 1}{\sqrt{y^2 - 1} }[/tex]
I am fairly confident that is correct because I keep on getting it.
Unfortunately, I can't seem to integrate this at all.
 
Last edited:

Answers and Replies

  • #2
378
2
[tex]
\int \frac{dN}{N} = cot(\theta_{max} ) \int_{0}^{\theta_{max} } \frac{2y^2 - 1}{\sqrt{y^2 - 1} }
[/tex]

If you are finding it hard to integrate the right side, try u = sqrt(y^2-1) .. fairly simple to integrate
 

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