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**hard kinematic problem, need...help...pls:)**

## Homework Statement

A policeman (on a motorcycle, with the engine going) is hiding behind a bush on the side of the road when a speeding truck passes with a speed of 96.5 km/h. As the truck passess he sets off with an acceleration of 1.83 m/s, which he maintains until he overtakes it. Calculate:

a) the time he took to overtake the truck

b) the distance he travelled in doing so

c) the velocity, in km/h, of the motor cycle when it catches the truck.

## Homework Equations

## The Attempt at a Solution

Well first i converted 96.5 hm/h into m/s which is 26.8 m/s and i know that his acceleration doesn't change, im just wondering is the policeman's final velocity the speed that the truck is travelling at which is 26.8 m/s? And is his initial velocity 0? and his acceleration is 1.83 so i thort that i cud use v=u+at to work out a)

i think im on the wrong track though actually I pretty sure I am. Can someone pls help me and also can sum1 pls tell me sum things that i shud look out for when trying to solve these really hard straight line motion questions. Like i get the simple ones but it is just ones similiar to these that i find difficult. I appreciate all the help!! Thankyou!!:)