- #1

Integral0

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T sub n = a + d(n-1)

Thanks!

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- Thread starter Integral0
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- #1

Integral0

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T sub n = a + d(n-1)

Thanks!

- #2

HallsofIvy

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I have no idea where you got this. There ARE "harmonic" progression (T_{n}= 1/n) and geometric progressions (T_{n}= a r_{n}) but the example you give T_{n} = a + d(n-1) is neither one, it is an "arithmetic" progression.

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- #3

selfAdjoint

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- #4

Integral0

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got it from my profe HallsofIVy

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MHB
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