Harmonic Motion/ max VelocityPlease Help

1. Apr 28, 2006

chazgurl4life

An object with mass 3.5 kg is attached to a spring with spring stiffness constant k = 300 N/m and is executing simple harmonic motion. When the object is 0.020 m from its equilibrium position, it is moving with a speed of 0.55 m/s.

b) Calculate the maximum velocity attained by the object. [Hint: Use conservation of energy.]

so if i use E= 1/2mv^2=1/2KX^2
then-->.5(3.5 kg)(.55) ^2= 1.5(300 N/m)(.200) ^2

but what does that prove ? I dont think this is right

2. Apr 28, 2006

Andrew Mason

You are right - your answer is not right.

Just add the kinetic and potential energy to find its total energy. Energy is conserved. So when potential energy = 0, kinetic energy = total energy. That is where it will have maximum speed.

AM

3. Apr 28, 2006

neutrino

That piece of information lets you calculate the potential and kinetic energies (at the point .02m from equillibrium). With that you can calculate the total energy of the system(E = P+K). Now how is this connected to the maximum velocity the object can have?

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