Harmonic motion problem

  • #1
chocolatelover
239
0
Hi everyone,

Could someone please help me with this problem?

Homework Statement


In an engine, a piston oscilates with simple harmonic motion so that its position varies according to the following expression, where x is in centimeters and t is in seconds.
x=5.00cmcos(3t+pi/5)

a. At t=0, find the position of the piston
b. What is its velocity?
c. What is its acceleration?
d. Find the period and amplitude of the motion


Homework Equations





The Attempt at a Solution



a. 5cmcos(3(0)+pi/5)=5cos(pi/5)=4.05cm

b. -5sin(pi/5)=-2.9

c. -5cos(pi/5)=-4.05

d. 5cm=amplitude

Thank you very much
 

Answers and Replies

  • #2
rock.freak667
Homework Helper
6,223
31
[itex]x=5cos(3t+\frac{\pi}{5})[/itex]

[tex]v=\frac{dx}{dt}=-5sin(3t+\frac{\pi}{5}) \times 3=-15sin(3t+\frac{\pi}{5}) [/tex]
 
  • #3
chocolatelover
239
0
Thank you very much

Regards
 

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