A 5 kg ball hangs from a 10 m strong. The ball is swung horizontally outward 90 degrees from its equilibrium position. Assuming the system behaves as a simple pendulum, find the maximum speed of the ball during its swing.(adsbygoogle = window.adsbygoogle || []).push({});

what would I have to do to figure this problem out?

[tex]\omega = \sqrt{\frac{g}{l}}[/tex]

[tex] \omega = \sqrt{\frac{9.8}{10}}[/tex]

[tex] \omega=0.99rad/s[/tex]

[tex]\omega r =v[/tex]

[tex]0.99rad/s* 10m =v[/tex]

[tex]v=9.9m/s[/tex]

I'm not getting the answer of 14, what am I doing wrong?

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# Homework Help: Harmonic motion

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