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Harmonic oscillator problem

  1. May 5, 2008 #1
    Hi everyone,

    Could someone please help me with this problem?

    1. The problem statement, all variables and given/known data

    A simple harmonic oscillator takes 11.5s to undergo four complete vibrations.

    a. Find the period of its motion
    b. Find the frequency in Hertz
    c. Find the angular frequency in radians per second

    2. Relevant equations

    ω=2pi(f)
    ω=spi/T
    f=ω/2pi

    t=1/f
    3. The attempt at a solution

    a. ω=2pi/11.5=.546
    f=.546/2pi=.858
    t=1/f=1.166

    b. f=.858

    c. ω=.546

    Thank you very much
     
  2. jcsd
  3. May 5, 2008 #2
    Nope, doesn't look right.

    So in order to go back and forth 4 times, it takes 11.5s, right? Your "period" is how long it takes to do this once.

    Secondly, frequency in Hz is f = 1/T

    Lastly, your angular frequency is w = (2*pi)/T
     
  4. May 7, 2008 #3
    Thank you very much

    Could you please explain to me how to find one of these? Once I can find one, I can find the others. It seems like there isn't enough information given, because the 11.5 s is not used in any of the equations, right?

    Thank you
     
  5. May 7, 2008 #4
    your period is 11.5s divided by 4, i think

    once you'be found your period, do the inverse to get your frequency

    divide frequency by 2pi, multiply by 60s to get rad/s

    i think i am correct, try it
     
  6. May 7, 2008 #5
    Thank you very much

    Isn't 11.5 just the time or is that also the period?

    Thank you
     
  7. May 7, 2008 #6
    no i think the problems means that it makes 4 cycles in 11.5 seconds, so a period equals the time of one cycle, so in order to find period from the given time, divide time by 4. try it.

    did it work out correctly?
     
  8. May 7, 2008 #7
    Yes, that was correct

    Thank you very much

    Regards
     
  9. May 7, 2008 #8
    no worries, glad to help
     
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