# Harmonic oscillator problem

1. May 5, 2008

### chocolatelover

Hi everyone,

1. The problem statement, all variables and given/known data

A simple harmonic oscillator takes 11.5s to undergo four complete vibrations.

a. Find the period of its motion
b. Find the frequency in Hertz
c. Find the angular frequency in radians per second

2. Relevant equations

ω=2pi(f)
ω=spi/T
f=ω/2pi

t=1/f
3. The attempt at a solution

a. ω=2pi/11.5=.546
f=.546/2pi=.858
t=1/f=1.166

b. f=.858

c. ω=.546

Thank you very much

2. May 5, 2008

### Poop-Loops

Nope, doesn't look right.

So in order to go back and forth 4 times, it takes 11.5s, right? Your "period" is how long it takes to do this once.

Secondly, frequency in Hz is f = 1/T

Lastly, your angular frequency is w = (2*pi)/T

3. May 7, 2008

### chocolatelover

Thank you very much

Could you please explain to me how to find one of these? Once I can find one, I can find the others. It seems like there isn't enough information given, because the 11.5 s is not used in any of the equations, right?

Thank you

4. May 7, 2008

### scholio

your period is 11.5s divided by 4, i think

once you'be found your period, do the inverse to get your frequency

divide frequency by 2pi, multiply by 60s to get rad/s

i think i am correct, try it

5. May 7, 2008

### chocolatelover

Thank you very much

Isn't 11.5 just the time or is that also the period?

Thank you

6. May 7, 2008

### scholio

no i think the problems means that it makes 4 cycles in 11.5 seconds, so a period equals the time of one cycle, so in order to find period from the given time, divide time by 4. try it.

did it work out correctly?

7. May 7, 2008

### chocolatelover

Yes, that was correct

Thank you very much

Regards

8. May 7, 2008