Harmonic oscillator with/without gravity

In summary, the conversation discussed the energy of a mass on a spring oscillating in linear motion and how it changes when gravity is turned on. It was noted that when the system is vertical, both gravitational potential energy and spring potential energy must be considered. The decrease in gravitational potential energy was found to be larger than the increase in spring potential energy, leading to the question of whether there is a general law stating that the energy of a system decreases when an external conservative force is applied. While there is no specific law, it was noted that the spring force will eventually overtake the gravitational force as the mass reaches its new equilibrium position.
  • #1
daudaudaudau
302
0
If I have mass on a spring that is oscillating in a linear motion, this system has a certain energy. Now if we imagine the system to be aligned along the vertical, why is the energy lower when gravity is turned on? I can calculate it and see that it is correct, but what is the "explanation" ? Because, I mean, when gravity is turned on, the string is stretched further, so this should increase the energy.
 
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  • #2
When the system is vertical, you must also consider gravitational PE along with spring PE. Compare the increase in spring energy (as it stretches to the new equilibrium point, say) with the decrease in gravitational PE.
 
  • #3
Right, and I can see that the decrease in gravitational PE is larger than the increase in the spring PE. Is there some general "law" stating that whenever you apply an external conservative force to a system, the energy decreases?
 
  • #4
daudaudaudau said:
Right, and I can see that the decrease in gravitational PE is larger than the increase in the spring PE.
That's only true if you compare the change in gravitational and spring PE as the masses lowers to its new equilibrium position. Since the gravitational force is constant, the spring force will soon overtake it. I don't see anything particularly significant about this. With respect to its new equilibrium point, a vertical spring+mass behaves similarly to a horizontal one.
Is there some general "law" stating that whenever you apply an external conservative force to a system, the energy decreases?
Not that I'm aware of.
 
  • #5


The addition of gravity to a harmonic oscillator system does indeed result in a decrease in energy. This can be explained by considering the forces acting on the mass on the spring. In a simple harmonic oscillator without gravity, the only force acting on the mass is the restoring force of the spring, which is directly proportional to the displacement of the mass from its equilibrium position. This results in a sinusoidal motion with a constant amplitude and energy.

However, when gravity is turned on, an additional force is introduced. Gravity pulls the mass downwards, causing it to stretch the spring further and increase the potential energy of the system. This results in a larger amplitude of oscillation and therefore a higher potential energy. However, as the mass moves downwards, it also gains kinetic energy, which allows it to overcome the increased potential energy and continue oscillating.

As the mass moves upwards, the opposite occurs. The potential energy decreases, but the kinetic energy also decreases as the mass slows down due to the restoring force of the spring. This results in a decrease in the total energy of the system.

In summary, the addition of gravity changes the balance between potential and kinetic energy in the system. This results in a decrease in the total energy of the system compared to a harmonic oscillator without gravity.
 

1. What is a harmonic oscillator?

A harmonic oscillator is a system that exhibits periodic motion, meaning it repeats the same pattern over and over again. It is typically described as a mass attached to a spring with a restoring force that is directly proportional to its displacement from its equilibrium position.

2. How does gravity affect a harmonic oscillator?

In the absence of external forces, a harmonic oscillator will continue to oscillate at its natural frequency. However, when gravity is introduced, it adds an additional force that can either increase or decrease the oscillation frequency depending on the direction and magnitude of the force.

3. What is the equation for a harmonic oscillator with gravity?

The equation for a harmonic oscillator with gravity is F = -kx - mg, where F is the net force, k is the spring constant, x is the displacement from equilibrium, and mg is the force of gravity.

4. How does the amplitude of a harmonic oscillator change with gravity?

The amplitude of a harmonic oscillator will decrease over time when gravity is present. This is because the force of gravity acts to dampen the oscillations, causing them to gradually decrease in size.

5. Can a harmonic oscillator with gravity reach equilibrium?

Yes, a harmonic oscillator with gravity can reach equilibrium if the damping force is strong enough to counteract the effects of gravity. In this case, the oscillations will eventually stop and the system will reach a stable equilibrium position.

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