- #1
induing
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hello,
new here and confused about Newton second Law.
given:
vertical mass damper system, position of the mass: x(t)=sin(t)
velocity is: v(t)=cos(t)
acceleration is: a(t)=-sin(t)
function x(t): above x-axis describes position of the mass below the vertical equilibrium point, which (below) is the positive direction of vector x
suppose I look at the movement between t=0 and t=T/4: when the mass is below the vertical equilibrium line and is moving to the ground
when I apply Newton second law (ma(t)) the vector a(t) must point downward because mass is going down, but when I look at the the function a(t) is it negative, which means the vector a(t) is pointing upward (ponting in negative direction)...
I'm off the right track, but don't see my fault..
so if anyone can help, please?
grtz
new here and confused about Newton second Law.
given:
vertical mass damper system, position of the mass: x(t)=sin(t)
velocity is: v(t)=cos(t)
acceleration is: a(t)=-sin(t)
function x(t): above x-axis describes position of the mass below the vertical equilibrium point, which (below) is the positive direction of vector x
suppose I look at the movement between t=0 and t=T/4: when the mass is below the vertical equilibrium line and is moving to the ground
when I apply Newton second law (ma(t)) the vector a(t) must point downward because mass is going down, but when I look at the the function a(t) is it negative, which means the vector a(t) is pointing upward (ponting in negative direction)...
I'm off the right track, but don't see my fault..
so if anyone can help, please?
grtz