- #1

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having problem with intergrate :

... _

_/ 4 / (x^2-2x-1) dx

thx

... _

_/ 4 / (x^2-2x-1) dx

thx

Last edited:

- Thread starter expscv
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- #1

- 241

- 0

having problem with intergrate :

... _

_/ 4 / (x^2-2x-1) dx

thx

... _

_/ 4 / (x^2-2x-1) dx

thx

Last edited:

- #2

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btw how to use maths input thing?

- #3

matt grime

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trig and latex, in that order.

- #4

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huh? i m not sure wats exactly.

- #5

matt grime

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- #6

matt grime

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[tex] \int\frac{1}{x^2-2x-1}dx[/tex]

click on the image and it should show you the source code for it

click on the image and it should show you the source code for it

Last edited:

- #7

HallsofIvy

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[itex]u^2-2= (u-\sqrt{2})(u+\sqrt{2})[/itex] and the integral can be done by partial fractions.

- #8

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[tex] \int \frac{4}{x^2-2x-1} dx = \int \frac{4}{(x-1)^2-2}dx [/tex]?

great thx

great thx

- #9

matt grime

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ah, apologies, it's hyperbolic trig, not trig.

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