Hi, I'm stuck. Can someone help me out? Problem: The properties of a certain fluid are related as follows: u=196+0.718t pv=0.287(t+273) (a)where 'u' is the specific internal energy(Kj kg), t is in degress Celsius, p is pressure(Kn/m2) and v is specific volume (m3 kg).For this fluid. Find Cp and Cv (b)A system composed of 2 kg of the above fluid expands in a frictionless piston and cylinder from an initial state of 1 Mpa, 100degrees Celsius to a final temp of 30degress Celsius.If there is no heat transfer, find the net work for the process. -------------------------------- This is what i have tried: in (a), i tried to link the two equations together, so that i could get 'u' and 'pv' in the same equation: u=196+2.5(pv-78.35) I'm stuck now.How do i proceed? i know the formula for cp and cv, which is Cp=(do)u/(do)t cv=(do)Q/(do)T .How do i use these formulas with respect to the above equation? (b)I'm totally confused on this one. I don't know where to start.All i could understand is to find the work done, and that Q=0. Thanks.