Having troubles wrapping my head around this design, also confused on directions

In summary, the conversation is discussing the design of a combinational circuit that takes in a 3-bit number and produces a 6-bit binary number output equal to the square of the input number. There is confusion about how to represent the input and output numbers in binary and how to create a truth table for the circuit. The solution is to use a 3-bit input and a 6-bit output, with the output being the result of multiplying the input number by itself (i.e. squaring it). The final step is to create a truth table with the appropriate inputs and outputs and then minimize the equation to create a simplified circuit design.
  • #1
mr_coffee
1,629
1
One of my questions say:
Designa combinational circuit that accepts a 3 bit number and generates a 6 bit binary number output equal to the sqaure of the input number.

Now when it says it wants a 3 bit number as the input does it mean like
ABC
000
001
010
011
100
101
110
111

then the output would be
000 000
000 001
how would u make a 6 bit output of 010 == 2 in decimal? maybe I'm confused, wait i know i am! can anyone help?
 
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  • #2
Wait i get it now...
if i would multiply
111
111
i would get
110001
but how would i implement that in a truth table?
like would it be
ABC DEFGHI
111 110001
Then my min term would be DE'F'G'HI ?
 
  • #3
I figured it out...
 
  • #4
I have the same question. Can you explain how you did this please? I need the table with inputs and ouput and the minimized equation for it.
 

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