HCl gas dissolves in water consisting of hydrochloric acid, or hydrochloric acid. HCl dissociates
fully ions as follows: HCl → H+ + Cl-.
a) Calculate the pH of the solution, which is made by dissolving 1.6 grams of HCl in 0.40 liters of water 298 K temperature.
b) How many ml it takes 0.050 mol/l NaOH solution, when it titraat 30 ml of 0.10 mol/l HCl solution?
The Attempt at a Solution
molar cencentration of H3O+ = n/V
n= 0.0438 mol
C= n/V = 0.0438/0.4 = 0.11 mol/l
PH = -log C of H3O+
PH = -log 0.11
PH = 0.96 (approximately)
HCl with NaOH
Ca*Va = Cb*Vb -------------- we search V of NaOH
Vb = (Ca*Va)/Cb
Vb = (0.10*0.03)/0.050
Vb = 0.06 L