For drawing a energy level diagram of He+ (singly ionized He), do I draw it without the interaction of the "outside" electron, thus no effect of orbital angular quantum number l (because there's only 1 electron left). Or should I draw it with the interaction with the "outside" electron, leading to the effect the orbital angular quantum number l make on the energy level? Because if I'm not wrong, the effect of l on energy levels is based on electron interaction, right? (I'm trying to draw an energy diagram explaining the spectrum of Helium)(adsbygoogle = window.adsbygoogle || []).push({});

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# He+1 energy level.

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