Head loss due to contraction

In summary, the degree of contraction in loss of head at entrance is influenced by the thickness of the pipe walls and the diameter of the pipe compared to its flow. The author also notes that the loss coefficient, represented by k, will vary for very thin tubes, resulting in a higher value for head loss. The equation for head loss is given as k(V^2)/2g, where V is the velocity of water. A diagram may help clarify this concept further.
  • #1
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Homework Statement


I was told that for loss of head at entrance , the degree of contaction depends on how thick the pipe walls is .
i really don't know the meaning , can someone clarify ? the author also stated that the loss coefficients will vary , for very thin tubes , k is very high ?
head loss = k (V^2) / 2g

Homework Equations




The Attempt at a Solution


as we can see , the haed loss is affected by velocity of water , how can thickness of pipe affect the head loss? [/B]
 
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  • #2
foo9008 said:

Homework Statement


I was told that for loss of head at entrance , the degree of contaction depends on how thick the pipe walls is .
i really don't know the meaning , can someone clarify ? the author also stated that the loss coefficients will vary , for very thin tubes , k is very high ?
head loss = k (V^2) / 2g

Homework Equations




The Attempt at a Solution


as we can see , the haed loss is affected by velocity of water , how can thickness of pipe affect the head loss? [/B]
Can you provide an exact quote?
 
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  • #3
Chestermiller said:
Can you provide an exact quote?
The degree of contraction depends upon how far the flow the pipe may project within the reservior and also how thick the pipe walls are , compared with its diameter
 
  • #4
foo9008 said:
The degree of contraction depends upon how far the flow the pipe may project within the reservior and also how thick the pipe walls are , compared with its diameter
Can you provide a diagram?
 
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  • #5
Chestermiller said:
Can you provide a diagram?
 

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  • #6
Edit : Inlet profiles illustration removed .
 
Last edited:
  • #7
Nidum said:
https://www.physicsforums.com/attachments/100868
What are you trying to say?
 
  • #8
Chestermiller said:
Can you provide a diagram?
do you have any idea now ?
 

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