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Headache about Kollatz algorythm

  1. Feb 6, 2005 #1
    who can prove that if we have x=((3^n)*m-1)/(2^k) where x and m are odd
    then x will be: x=(2^(n-1))*m1-1 where m1 is odd? is it possible to prove it?
     
  2. jcsd
  3. Feb 8, 2005 #2
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