1. Sep 13, 2013

### quawa99

Is it possible to determine which side of a coin is going to turn up when you toss one?If possible what all information would be required to do so?

2. Sep 13, 2013

### SteamKing

Staff Emeritus
You about to enter a big quarter flipping contest?

3. Sep 13, 2013

### quawa99

Its just out of curiosity nothing more.

4. Sep 13, 2013

### quawa99

Assuming that we know the impulse imparted to the coin,the point of application of impulse ,the dimensions and mass of the disc:
1)The angular velocity of the coin can be calculated.
2)The time of flight can be calculated.

Based on the above two values we can find out the angle the coin rotates which can help us know which face of the coin is facing up.
I have neglected air resistance and considered the angular velocity to be constant.Tell me if this is correct or not.

Last edited: Sep 13, 2013
5. Sep 13, 2013

### jbriggs444

You also need to know

1) The height above the floor and the orientation of the coin when the impulse is applied.
2) Any existing rotation and velocity of the coin when the impulse is applied.
3) Details on the coin and floor surface that control how the coin bounces when it hits the floor at various possible orientations with various impact speeds and various rotation rates.

In addition, it is not clear that imparting the impulse will result in a pure rotation about a single horizontal axis.

6. Sep 13, 2013

### quawa99

It doesn't need to rotate purely about a horizontal axis does it?
Anyway the impulse will give the center of mass a linear vertical velocity plus some angular moment about a horizontal axis passing through it.So the coin undergoes rotational as well as translatory motion.The angular momentum about the axis passing through the center of mass should remain constant as gravity is the only force which cannot cause any torque.Hence the angular velocity will remain constant.

7. Sep 13, 2013

### jbriggs444

The impulse will not neccessarily give an angular moment about a horizontal axis. It may include a component about a vertical axis.

Angular velocity in three dimensions is more complex than in two.

8. Sep 13, 2013

### quawa99

What if the disc is kept horizontal and a perfectly vertical impulse is given

9. Sep 13, 2013

### jbriggs444

Yes, that should give pure rotation around a horizontal axis, allowing the problem to be reduced to a two dimensional treatment.