Here is the problem. 50g of liquid is heated by 30 degrees in a calorimeter in 530 seconds. The power is 10W. 100g is heated by the same amount in the same time with a power input of 16.1W. What is the s.h.c (Cs)of the liquid. I know that: Cs = (1/mass) x (dH/dt for liquid) + (dH/dt for calorimeter) and thus I have a set of two simultaneous equations which can be solved for Cs. I also know (well, I think I do) that dH/dt for the calorimeter is equal to the power input. The questions is, what is dH for the liquid? Am I barking up the right tree in the first place?