The heat capacity of lead is 0.130 J/g C. How many joules of heat are required to raise the temperature of 28.5 grams of lead from 15 to 37?(adsbygoogle = window.adsbygoogle || []).push({});

For this problem the formula that must be used is q = m*C*deltaT, where mass is expressed in g?

q = m*C*deltaT

q = (0.130 J/g*C)*(28.5 g Pb)*(37 - 15 C) = + 81.5 J

Is my sign correct?

The formula q = m*C*deltaT, where m is expressed in grams per g/mol (Pb's molar mass), is not being asked in this question, right?

Thanks.

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# Heat Capacity and Heat

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