The heat capacity of lead is 0.130 J/g C. How many joules of heat are required to raise the temperature of 28.5 grams of lead from 15 to 37? For this problem the formula that must be used is q = m*C*deltaT, where mass is expressed in g? q = m*C*deltaT q = (0.130 J/g*C)*(28.5 g Pb)*(37 - 15 C) = + 81.5 J Is my sign correct? The formula q = m*C*deltaT, where m is expressed in grams per g/mol (Pb's molar mass), is not being asked in this question, right? Thanks.