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## Main Question or Discussion Point

hey for this question

If a 2kg sample of aluminium absorbs 64.4 kJ of heat from its surrounds by how much does its temperature increase

the answer is 65.1

how? i got 32.5

q=mcT

T=q/mc=(64.6x10^3)/(2000x.9930)

also same for this question

If 0.5g of an organic compound is completely combusted in air in a constant press calorimeter with a heat capacity of 510 J K-1 a temperature rise of 5.9 degrees is recorded. The heat of combustion (kJ g-) of the compound is approximately

the answer is 3009...

i convered C to c then used q=mcT

which gave me 3009 J , so shouldnt it be 3.00 kJ

so 3.00/0.5 to get kJ per gram

If a 2kg sample of aluminium absorbs 64.4 kJ of heat from its surrounds by how much does its temperature increase

the answer is 65.1

how? i got 32.5

q=mcT

T=q/mc=(64.6x10^3)/(2000x.9930)

also same for this question

If 0.5g of an organic compound is completely combusted in air in a constant press calorimeter with a heat capacity of 510 J K-1 a temperature rise of 5.9 degrees is recorded. The heat of combustion (kJ g-) of the compound is approximately

the answer is 3009...

i convered C to c then used q=mcT

which gave me 3009 J , so shouldnt it be 3.00 kJ

so 3.00/0.5 to get kJ per gram