- #1

Dx

I said 52.5J

w=e*q_h =

.35 * 150 =

52.5

its wrong

what did i do wrong with this calculation. unless it mean 150J of put in. can anyone please explain this to me.

TY!

dx

- Thread starter Dx
- Start date

- #1

Dx

I said 52.5J

w=e*q_h =

.35 * 150 =

52.5

its wrong

what did i do wrong with this calculation. unless it mean 150J of put in. can anyone please explain this to me.

TY!

dx

- #2

Tom Mattson

Staff Emeritus

Science Advisor

Gold Member

- 5,500

- 8

Can you post the definition of efficiency from your book?

- #3

Dx

efficiency(e) = W(work out) / Q_H(work in)

- #4

Tom Mattson

Staff Emeritus

Science Advisor

Gold Member

- 5,500

- 8

That's what I thought. OK, just plug-n-chug.Originally posted by Dx

efficiency(e) = W(work out) / Q_H(work in)

(You know, it's always possible that the book is wrong!)

- #5

Dx

I thought i did that like shown but aparently its not right. I just wanted to know does your answer match mine?Originally posted by Dx

A heat engine has efficiency of 35% and recieves 150J heat per cycle. how much work dos it perfrom in each cycle?

I said 52.5J

w=e*q_h =

.35 * 150 =

52.5

Dx

- #6

Tom Mattson

Staff Emeritus

Science Advisor

Gold Member

- 5,500

- 8

Yes, it does.

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