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Heat energy

  1. Mar 29, 2008 #1
    1. The problem statement, all variables and given/known data

    from the following observations made during an experiment, determine the specific latent heat of vaporisation of water.

    initial mass of water 400g, final mass of water 450g (the extra is condensed steam)

    mass of calorimeter 200g, initial temp of water & calorimeter 16 C

    final temp of water & calorimeter 70 C , specific heat capacity of water 4200j/kg C

    specific heat capacity of calorimeter 420 j/kg C

    HINT heat lost by steam= heat gained by water + heat gained by calorimeter


    2. Relevant equations

    quantity of heat = mass x specific heat capacity x temperature change

    3. The attempt at a solution

    let suffix c = calorimeter
    w = water

    mc cc tc = mw cw tw + fmw cw t

    -200 x 420 ( 70 tc) = 400 x 4200 ( 16 t) + 450 x 420 ( 16 t)

    - 84000 ( 70 tc) = 168,0000 ( 16 t) + 189,000 (16 t)

    -84000 ( 70 tc) = 1869000 ( 16 t)

    - 84000 c + 5.88 x 10 6 = 1869000 c 29.904 x 10 6

    5.88 x 10 6 +29.904 x 10 6 = 1869000 c 84000 c


    35.784 x 10 6 = c (1869000 + 84000 ) = 1953000 c


    c = 35.784 x 10 6 / 1953000 = 18.322 C


    MY TUTOR HAS SAID MY FORMULA IS INCOMPLETE BUT I DONT NO WHERE I HAVE GONE WRONG PLEASE HELP MARK.
     
  2. jcsd
  3. Mar 30, 2008 #2
    can anyone help ?
     
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