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Heat engine (isovolumeric process)

  1. Oct 29, 2005 #1
    A heat engine has the three step cycle shown above. Starting from point A, 1 L (liter) of ideal gas expands in the isobaric (constant pressure) process A to B at P = 2 atm. B to C is isovolumetric process at V = 5 L, and C to A is an isothermal (constant temperature) compression at 300 K. (Note that the diagram is illustrating V vs P. This should make no difference in your calculations. )

    Find the heat (in J) exhausted in the process B to C if the internal energy of the gas U = 5.0J/K * T

    i'm having trouble with this one,

    it says to find Q exhausted,since it's isovolumetric, W=0, thus delta U = Q

    I found the temperature to B, and tried this equation:

    delta U = 1.5 n R (T(c) - T(b))

    didn't work....

    i just don't know what to do with the internal energy given...any hints?

    (i've already calculated pressure at C to be .4 atm)

    Attached Files:

  2. jcsd
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