1. The problem statement, all variables and given/known data A heat engine operates between 40°C and 380°C. Being a real engine, its efficiency is only 60% of that theoretically possible for a Carnot engine at these temperatures. If it absorbs heat at a rate of 60 kW, at what rate does it exhaust heat? 2. Relevant equations e = 1 - TL/TH --> Carnot Efficiency e = 1 - QL/QH --> Efficiency 3. The attempt at a solution 1) First I changed the temperatures to Kelvins, then I calculated the Carnot efficiency: e = 1 - (313/657) = 1 - 0.48 = 0.52 2) Then I determined the actual efficiency to be: 0.52 x 0.60 = 0.31 or 31% 3) Finally I plugged in the efficiency in 2 to the 2nd equation above: 0.31 = 1 - (QL/60 kW) 60(0.31) = 60 - QL 18.72 = 60 - QL QL = 41.3 kW So therefore the engine exhausts heat at 41.3 kW or 41.3 kJ/s. I think I did this right, but I'm the type of guy who always manages to forget something or other. Does this look right?