Heat-Equilibrium temp

  • Thread starter Dx
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  • #1
Hello,

what will be the equilibrium temperature when a 270 g block of copper at 300 degrees C is placed in a 150 g Al calorimeter cup containing 820 g of water at 12 degree C?

My answer is 20.2 C Is this correct?

I done is like so 270 * (390)*(300-T) = (820)*(900)(T-12) sorry but i forgot where I referenced this formula, I think i am confused with this problem though. It doesn't seem right to me so i thought i would ask?

Thanks!
Dx
:wink:
 

Answers and Replies

  • #2
quantumdude
Staff Emeritus
Science Advisor
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Originally posted by Dx
I done is like so 270 * (390)*(300-T) = (820)*(900)(T-12) sorry but i forgot where I referenced this formula,

The formula is:

Heat lost by copper = Heat gained by water

Where the heat (q) transferred to/from a body is given by:

q=mC(Thot-Tcold)

m=mass
C=specific heat
Thot=higher temp
Tcold=lower temp

The problem with your solution is that you need:

Heat lost by copper = Heat gained by water and aluminum

If you include the aluminum, you will get this right.
 

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