- 1,380

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**1. Homework Statement**

An aluminum vessel of 500 gr contains 117.5 gr water at 20

^{0}C. a piece of iron of mass 200 gr and 75

^{0}C is thrown inside. what's the final temperature and the water equivalent of the vessel.

**2. Homework Equations**

Specific heat of aluminum: 0.217

Specific heat of iron: 0.113

**3. The Attempt at a Solution**

##(500\cdot 0.217+117.5)(t-20)=200\cdot 0.113 (75-t)\rightarrow t=25^0##

The answer should be 23

^{0}C.

The water equivalent:

##500\cdot 0.217=m=108.5 gr##

The answer should be 110 gr