Two 0.525 m rods, one lead and the other copper, are connected between metal plates held at 2.00°C and 106°C. The rods have a square cross section of 1.50 cm on a side. How much heat flows through the two rods in 1.0 s? Assume no heat is exchanged between the rods and the surroundings. Relevant equations Q=kA(ΔT/L)t k for Pb is 34.3 k for Cu is 395 My attempt I set up the equation for the rods in the exact same manner. Q=(34.3)(1.77e-4)(104/.0150)(1) Q=(395)(1.77e-4)(104/.0150)(1) I know what is incorrect about these equations is the area I am using. I took the square cross section to mean diameter, which evidently it is not. The answers given in the text are: Q=(34.3)(.0151)^2(104/.0150)(1) Q=(395)(.0151)^2(104/.0150)(1) How should I interpret square cross section in the future? To finish this problem I am aware that Qtotal=QPb+QCu Thanks!