- #1

cashellz77

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## Homework Statement

heat Lost Heat Gained

M=.213 kg M=.868

C=2090 J/kg K C=4186 J/kg K

To=0 To=26.5

T=? T=?

## Homework Equations

Q=mc(delta T

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- Thread starter cashellz77
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- #1

cashellz77

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heat Lost Heat Gained

M=.213 kg M=.868

C=2090 J/kg K C=4186 J/kg K

To=0 To=26.5

T=? T=?

Q=mc(delta T

- #2

Andrew Mason

Science Advisor

Homework Helper

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Heat flows from the hotter to the colder until they reach the same temperature. So you know that the temperature of each mass will be the same when equilibrium is reached. You have to determine the final temperature.## Homework Statement

heat Lost Heat Gained

M=.213 kg M=.868

C=2090 J/kg K C=4186 J/kg K

To=0 To=26.5

T=? T=?

## Homework Equations

Q=mc(delta T

## The Attempt at a Solution

I can not figure this out , I have tried and tried with no luck.

Your equation for the heat flow is correct. So the equations for the change in temperature in terms of initial and final temperature are:

[tex]Q_1 = m_1C_1(T_1 - T_f)[/tex]

[tex]Q_2 = m_2C_2(T_f - T_2)[/tex]

What is the relationship between Q1 and Q2? That will enable you to solve for Tf.

AM

Last edited:

- #3

Delphi51

Homework Helper

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I don't think you have typed in the whole question - not exactly sure what the question is!

Generally in these heat questions you write

heat lost by one material = heat gained by the other

mC*ΔT = mC*ΔT

I think your ΔT for the water will be (26.5 - T) where T is the final temperature.

For the other material, looks like ΔT = (T - 0).

Try putting all the info into the equation and see if you can find T.

- #4

cashellz77

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- #5

Delphi51

Homework Helper

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heat lost by water = heat of fusion of ice + heat gained by ice after melting

You should look up "heat of fusion" in your book and get the formula for it.

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