# Heat loss/Heat Gained

• cashellz77
You will also need to look up the specific heat of ice, and of water. Then you can use the formula I gave you in my earlier post to calculate the final temperature of the water.In summary, the question asks for the final temperature of the water after an ice cube with a mass of 0.213 kg and a temperature of 0.00°C is placed in a Styrofoam cup containing 0.868 kg of water at a temperature of 26.5°C. The equation to use is Qlost = Qgain, where the heat lost by the water is equal to the heat of fusion of the ice plus the heat gained by the melted ice. The specific heat of ice and water are needed

## Homework Statement

heat Lost Heat Gained
M=.213 kg M=.868
C=2090 J/kg K C=4186 J/kg K
To=0 To=26.5
T=? T=?

Q=mc(delta T

## The Attempt at a Solution

I can not figure this out , I have tried and tried with no luck.

cashellz77 said:

## Homework Statement

heat Lost Heat Gained
M=.213 kg M=.868
C=2090 J/kg K C=4186 J/kg K
To=0 To=26.5
T=? T=?

Q=mc(delta T

## The Attempt at a Solution

I can not figure this out , I have tried and tried with no luck.
Heat flows from the hotter to the colder until they reach the same temperature. So you know that the temperature of each mass will be the same when equilibrium is reached. You have to determine the final temperature.
Your equation for the heat flow is correct. So the equations for the change in temperature in terms of initial and final temperature are:

$$Q_1 = m_1C_1(T_1 - T_f)$$

$$Q_2 = m_2C_2(T_f - T_2)$$

What is the relationship between Q1 and Q2? That will enable you to solve for Tf.

AM

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Welcome to PF, Cashelz.
I don't think you have typed in the whole question - not exactly sure what the question is!

Generally in these heat questions you write
heat lost by one material = heat gained by the other
mC*ΔT = mC*ΔT

I think your ΔT for the water will be (26.5 - T) where T is the final temperature.
For the other material, looks like ΔT = (T - 0).
Try putting all the info into the equation and see if you can find T.

Hello Thankyou! The queastion reads An ice cube with a mass of .213kg and a temp. of0.00c is placed in a Styrofoam cup containing .868 of water at a temp. of 26.5 c . What is the final temp. of the water after the ice cube has melted?

Glad you gave us the question! Our previous answers do not apply to this question, which involves the melting of ice. It takes heat to melt ice, called the heat of fusion. So
heat lost by water = heat of fusion of ice + heat gained by ice after melting

You should look up "heat of fusion" in your book and get the formula for it.