How Is Heat Calculated in a Diesel Cycle Using Volumes and Temperatures?

In summary, the ideal gas cycle for a diesel engine is as follows: 1. Perform an adiabatic compression to a certain volume 2. Perform an adiabatic expansion to a higher volume 3. Finally, it moves back to the original volume while decreasing temperature.
  • #1
cloud809
3
0
1. Ideal gas cycle - diesel engine cycle. You begin at some volume V1. Perform an adiabatic compression to V2. Perform an expansion to V3 at constant pressure. Next, perform an adiabatic expansion to V4, Last, it moves back to V1 at a fixed volume, while decreasing temperature back to original starting point.

300px-DieselCycle_PV.svg.png

NOTE: Ignore "specific volume," and just consider it to be generic "volume" for my case.

Find Qin and Qout in terms of V1, V2, V3, and T1.


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2. 1st law: ΔU = W + Q, where W = -∫PdV

We're told that the 1st law is the assumed starting point for this problem.


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3. For Qin, I began that ΔU = 0 for 2→3, so -W2→3=Qin. This yielded

Qin=- (-∫23PdV)

or Qin = P(V3-V2).

Am I right to assume that ΔU=0 for this 2→3 phase? I can't find how to incorporate V1 and T1 if my method was ok.

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Then, for Qout, I noted that W = 0 for 4→1, so ΔU4→1=Qout.

So, I found that ΔU = Nk(f/2)BΔT, or Qout = NkB(f/2)(T1-T4). And again, I'm running into the same issue of not filling the parameters of the original question.
 
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  • #2
One thing I just realized is that for 2→3, I shouldn't have said ΔU = 0. Instead, I should have set up Qin as:

Qin = ΔU - W, where

ΔU = NkB(f/2)ΔT

ΔU = NkB(f/2)[(PV3-PV2)/NkB]

and W is still W=-P(V3-v2)

so, once simplified (Qin = ΔU - W), Qin=P[V3((f/2)+1)-V2((f/2)+1)].

This still doesn't put it in terms of V1, V2, V3, T1 however.
 
  • #3
cloud809 said:
so, once simplified (Qin = ΔU - W), Qin=P[V3((f/2)+1)-V2((f/2)+1)].

This still doesn't put it in terms of V1, V2, V3, T1 however.
Try to express P in terms of volume and temperature. Don't forget the adiabatic law ##TV^{\gamma-1} =## const.
 
  • #4
Thanks for the reply TSny.
I've considered something similar and figured it out I believe.
I used P1V11+f/2=P2V21+f/2, solved for P2, and substituted that into my Qin equation. And since there was still a P1 in there, I used the PV=NkBT for P1 to put it in terms of T1. Now my Qin satisfies all 4 variables (V1, V2, V3, T1).

Now to spend a bit more time and figure out Qout...
 
  • #5
Sounds good!
 

What is the "Heat of a Diesel Cycle"?

The heat of a diesel cycle refers to the amount of heat energy that is added to the engine during the combustion process in order to produce power.

How is the heat of a diesel cycle different from other types of engines?

The heat of a diesel cycle is different from other types of engines because it uses compression ignition instead of spark ignition, resulting in a higher compression ratio and a more efficient use of fuel.

What factors can affect the heat of a diesel cycle?

The heat of a diesel cycle can be affected by several factors, including the compression ratio, fuel injection timing, air-fuel ratio, and fuel properties such as cetane number and viscosity.

What are the benefits of having a higher heat of a diesel cycle?

A higher heat of a diesel cycle can lead to increased efficiency and power output, as well as lower fuel consumption and emissions. It also allows for the use of alternative fuels with lower energy content.

How is the heat of a diesel cycle measured and calculated?

The heat of a diesel cycle is measured and calculated using various parameters such as engine displacement, air-fuel ratio, and fuel properties. It can also be calculated using specialized software or through experimental testing on a dynamometer.

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