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## Homework Statement

the heat of fusion of water is 6.01 kj/mol. the heat capacity of liquid water is 75.3 j/mol*k. the conversion of 50g of ice at 0 degrees C to liquid water at 22 degrees C requires _____kj of heat.

## The Attempt at a Solution

i converted grams of ice to mols and got 2.778

then i multiplied by the heat capacity of 75.3 and the change in temperature of 22

i then converted 4601.667j to 4.601kj and added the heat of fusion 6.01kj/mol

i got an answer of 10.611kj but my study guide says the answer should be 21.3kj and im not sure where in my calculations i went wrong....could someone please help?