Homework StatementGiven that for the reaction KOH(aq) + HCL(aq) ----> KCL(aq) + H2O(l) H = - 54kjmol^-1.
What is the quantity of heat involved in the reaction? 2NaOH(aq) + H2SO4(aq) ----> Na2SO4(aq) + 2H2O(l)?
Heat of reaction Hrn =heat content of product Hp - heat content of reactant Hr. It can be written as Hrn= Hp-Hr
The Attempt at a Solution
Since Hrn=Hp-Hr. I don't know what to do again in other to get the value of Hp and Hr so that I can take the difference and Hrn will appear from no where.